Alberto <jac### [at] usbve> wrote:
:> -1/0 = -infinity

:  So,  -infinity*0 = -1 ?

  Nope. You are thinkin here "I translate the 0 from the left hand side to
the right hand side".
  This way of thinking is mathematically incorrect.
  When you have this:

  a/b = c

and you convert to this:

  a = c*b

you are not "translating" the 'b' from lhs to rhs, but you are multiplicating
both sides with 'b'. That is, if we put an extra step in between, we can see
what's really happening:

  a/b = c  <=>  (a/b)*b = c*b  <=>  a = c*b

  It's mathematically correct to multiply both sides with the same value.

  Now, in this case we have:

  -1/0 = -infinity

  What you are trying to do is to multiply both sides with 0:

<=>  (-1/0)*0 = -infinity*0  <=>  0/0 = -infinity*0

  Both, 0/0 and -infinity*0 are undefined. And 0/0 certainly is NOT the
same as -1.

-- 
main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
):_;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*- Warp -*/

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