In article <8F6177D69dashixpressnet@204.213.191.228> , das### [at] x-pressnet 
(daishi) wrote:

> 'partially' which means win98 is cooporative......(just like mac OS, not
> counting X of course)

No, it is pre-emptive with a monolithic operating system.  If you write a
simple application that just executes a loop lets say 10 billion times, will
the other applications still get a share of the processor?  Yes, because the
operating system will interrupt it after a few milliseconds and then switch
to another application.  This is pre-emptive multitasking.

On a Mac with i.e. Mac OS 9 an application executing the same program will
not share the processor with other applications until it calls the operating
system and allows it.  This is co-operative multitasking.

The difference between Win 9x and Win NT/2000 is the quality (and
probability method) of the scheduling algorithms, but they are still both
pre-emptive.
In fact this is one of the major improvements in Win 9x since Win 3.x.


     Thorsten


PS: If you don't believe me, get any recent CS textbook on operating
systems, and it will tell you Win 9x and NT both use pre-emptive
multitasking :-)


____________________________________________________
Thorsten Froehlich, Duisburg, Germany
e-mail: tho### [at] trfde

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