It DOES beg the question, however, as to whether we could get a function which
is linear, or

volumefractfilled= threshold.


Nathan Kopp wrote:

> Simen Kvaal <sim### [at] studentmatnatuiono> wrote...
> >
> > If the graph shows how much space is filled when a certain threshold is
> > used, e.g. it shows how many output-values of that value is used, the red
> > line should not be the one for version 0.5. Let's say the threshold is 0.
> > Then the graph at x-value 0 would show zero if the function had no
> plateaus,
> > because if it _had_ such plateaus, then space would be filled at threshold
> > zero. If the function had no plateaus, there would be no (very few)
> > output-values at zero. Therefore, no space should be filled. My point is:
> > the graphs must be correct.
> >
>
> Doh.  You are correct.  I was looking at the problem totally backwards.
>
> -Nathan

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