Chris Huff <chr### [at] yahoocom> wrote:
: True for most of these, but the COLOUR type is an array of 3 floats, not 
: doubles.

  So we get:
  786432*(3*4+3*8+2*8+8+6*8+3*8) = 103809024 bytes = 99 Megabytes.

  Not much difference.

: Currently, only the needed data is saved.

  But if the function uses all the parameters, it will take the maximum
amount?

  If the function is applied in a pixel-by-pixel basis, regardless of the
other pixels, why can't it be done on the fly, as someone else suggested?
It would certainly save lots of memory and/or disk space usage.
  And I don't think that writing and then reading 100 Megs of data to/from
disk is the fastest operation possible...

-- 
main(i,_){for(_?--i,main(i+2,"FhhQHFIJD|FQTITFN]zRFHhhTBFHhhTBFysdB"[i]
):5;i&&_>1;printf("%s",_-70?_&1?"[]":" ":(_=0,"\n")),_/=2);} /*- Warp -*/

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