Mike <pov### [at] aolcom> wrote in message news:37F03EC1.A53D7734@aol.com...
> I think I know what you are saying, but the way I'm doing it fits in with
the
> new sample_media function, so each time a supersample is taken it's added
into
> the total emission.  Then later it's divided by the total number of
samples for
> that interval.
>

That will cause a problem, though.  Uneven sampling (which is the result of
supersampling) needs uneven weights for the averaging process.  A simple
sum-and-divide will not give desired results.  I know, since I tried it.
;-)

-Nathan

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