Hi Dave

#if (clock<=1)
  translate <0, clock*20, 0>
#else
  #if (1<clock<=2)
    #declare elseclock = clock-1
    translate <0, 20, 0>
    rotate <0, 0, ((clock-1)*180)>
  #else
    #if (2<clock<=3)
      translate <0, -20, 0>
    #else
      #if (clock<=4)
        #declare elsclock= clock-3
        translate (-20+(20*(clock-3)))*y
      #end
    #end
  #end
#end

Why it doesn't work: (or so I believe)
(1<clock<=2)
pov first evaluates 1<clock and returns either false (=0) or true
(=1), then it check the resulting boolean<=2, which is always true...
you should write ((1<clock)&(clock<=2)).

However, there is a simpler way to do this: #switch

#switch (clock) // use clock for all tests
  #range (0,1) // if 0<=clock<=1, then...
    translate <0, clock*20, 0>
  #break //<-- this exit the #switch test, so #range(1,2) isn't used
too when clock=1
  #range (1,2)
    translate <0, 20, 0>
    rotate <0, 0, ((clock-1)*180)>
  #break
  #range (2,3)
    translate <0, -20, 0>
  #break
  #range (3,4)
    translate (-20+(20*(clock-3)))*y
  #break // this one isn't necessary... but it is neater this way.
  #else
    #error "\nClock out of range" // just for fun
#end // close the #switch directive

#switch uses also #case(aValue), but in this case this isn't very
usefull - except if you want subliminal images :-) See the doc.

Hope this helps,

Povingly,

Philippe

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