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Hi, i'm a new user, and i have to do for a course, this images: the inside of a
palace in rome.
So, using only few while cycle and macro, can anyone help me to do this in a
beautiful and simple way??? Please, is very important, thank you in anyway!
http://1.bp.blogspot.com/_Aq2WzR0aua8/RfBZBDnKEQI/AAAAAAAAAQU/HD1Q__Lm1Js/s500/nervi3.jpg
http://www.itgdellaporta.it/album/foto-album/Roma-2010/Nervi3-800.jpg
http://www.exibart.com/foto/80294.jpg
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Am 16.06.2011 22:01, schrieb simplyfabio:
> Hi, i'm a new user, and i have to do for a course, this images: the inside of a
> palace in rome.
> So, using only few while cycle and macro, can anyone help me to do this in a
> beautiful and simple way??? Please, is very important, thank you in anyway!
I'd suggest the following procedure:
(1) read any relevant written course material;
(2) if necessary read the "Getting Started" section in the docs, and
look up "#while" and "#macro";
(3) toy around with them a bit;
(4) figure out the symmetric properties of that palace;
(5) try yourself, maybe starting with a somewhat simplified version of
the palace;
(6) if you have any /specific/ questions or problems, ask here.
Don't expect anyone here to do your homework for you.
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clipka <ano### [at] anonymousorg> wrote:
> Am 16.06.2011 22:01, schrieb simplyfabio:
> > Hi, i'm a new user, and i have to do for a course, this images: the inside of a
> > palace in rome.
> > So, using only few while cycle and macro, can anyone help me to do this in a
> > beautiful and simple way??? Please, is very important, thank you in anyway!
>
> I'd suggest the following procedure:
>
> (1) read any relevant written course material;
>
> (2) if necessary read the "Getting Started" section in the docs, and
> look up "#while" and "#macro";
>
> (3) toy around with them a bit;
>
> (4) figure out the symmetric properties of that palace;
>
> (5) try yourself, maybe starting with a somewhat simplified version of
> the palace;
>
> (6) if you have any /specific/ questions or problems, ask here.
>
>
> Don't expect anyone here to do your homework for you.
Thanks for reply!
Then, i know thatt anyone make it for me! I've only asked some help input to
follow and try by myself.
I've studied it, and The only thing where i found problem is write a function
for one of that "arms". It is like a parabolic arc curved in two dimension, or a
sinxsinx function from 0 and pi/2 and mirrored... I don't know....
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On 17/06/2011 6:51 AM, simplyfabio wrote:
> Thanks for reply!
> Then, i know thatt anyone make it for me! I've only asked some help input to
> follow and try by myself.
> I've studied it, and The only thing where i found problem is write a function
> for one of that "arms". It is like a parabolic arc curved in two dimension, or a
> sinxsinx function from 0 and pi/2 and mirrored... I don't know....
You might not realise that if you put a series of straight objects in a
line and each object deviates slightly from the straight line of the
previous object. It will look like a continuous curve.
I know that you want to do your own homework but below is an example of
how a cylinder can be turned into a hoop. (The shorter the cylinder and
Analyse your subject and break it down into separate patterns that you
can model then combine them.
It might be an idea to work in 2D to start off with then move on to 3D.
#declare Cylinder0 =
cylinder {
-0.50*y,0.50*y,1.0
scale <1.0,4.0,1.0>
rotate <0.0,0.0,90.0>
translate <0.0,0.0,44.425>
} // end Cylinder0
union { // Object_Array0
#declare Count = 0;
#while( Count < 35 )
object{ Cylinder0
rotate <0.0*Count,5.0*Count,0.0*Count>
}
#declare Count = Count + 1;
#end
texture {
pigment {
colour rgbft <1.000,1.000,1.000,0.000,0.000>
}
finish {
ambient rgb <0.100,0.100,0.100>
brilliance 1.000
diffuse 0.600
}
}
} // end Object_Array0
--
Regards
Stephen
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Am 17.06.2011 07:51, schrieb simplyfabio:
> clipka<ano### [at] anonymousorg> wrote:
>> Am 16.06.2011 22:01, schrieb simplyfabio:
>> (6) if you have any /specific/ questions or problems, ask here.
>>
>>
>> Don't expect anyone here to do your homework for you.
>
> Thanks for reply!
> Then, i know thatt anyone make it for me! I've only asked some help input to
> follow and try by myself.
Sorry if I sounded excessively harsh, but your original posting was
pretty unspecific; now this:
> I've studied it, and The only thing where i found problem is write a function
> for one of that "arms". It is like a parabolic arc curved in two dimension, or a
> sinxsinx function from 0 and pi/2 and mirrored... I don't know....
... is what I'd call a specific question.
It seems to me that the "nodes" in the roof lie on circles having a
constant distance to one another, so that's what I'd try as a first
approach; i.e., each arc would follow a curve defined by:
y = sin(alpha)
x = cos(alpha) * cos(beta)
z = cos(alpha) * sin(beta)
beta = alpha * const1 + const2
where alpha is the "elevation" angle, and beta is the angle of rotation
about the vertical. const1 would be the same for all arcs, while const2
would be different for each arc
Of course the coordinate origin would be way below the surface.
If that turns out to not match the geometry, here's a few other
approaches that might make some sense:
- Presume that the "nodes" lie on circles having a constant /horizintal/
distance to each other, and that they lie on a sphere.
- Presume that the "nodes" lie on circles having a constant /horizintal/
distance to each other, and that they lie on a parabola.
- Presume that the distances between any two nodes on the same arc are
constant, and that they lie on a sphere.
- Presume that the distances between any two nodes on the same arc are
constant, and that they lie on a parabola.
In any case, it is a pretty safe bet that the roof is either a spherical
section or - actually even more likely - a parabola.
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