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|  |  | I would like to use pov to render a view like the
own drawn below for a box
  +--+
 /  /|
+--+ |
|  | +
|  |/
+--+
It's just the classical 3D technical drawing...
It looks like the orthographic camera, but 
increase of the z is transformed as p*(x+y),
with p either 1/2, 1 or 3/4 ...
Have anybody any suggestion on how to achieve that ?
 (with all pov-object, of course, not only the box).
 Post a reply to this message
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|  |  | This may be obvious to others as well, I can't make out your intention
exactly.  I'd suggest posting a drawing if you could.  I'd suggest
HTML formatted posting but that's NOT a good idea since people have a
difficult time with them.  Also I flunked out of being a
"advanced-user" so I probably shouldn't even be here.
 ; b
Bob
J. Grimbert <jgr### [at] atos-group com> wrote in message
news:37D38620.7E9E491A@atos-group.com...
>
> I would like to use pov to render a view like the
> own drawn below for a box
>
>   +--+
>  /  /|
> +--+ |
> |  | +
> |  |/
> +--+
>
> It's just the classical 3D technical drawing...
> It looks like the orthographic camera, but
> increase of the z is transformed as p*(x+y),
> with p either 1/2, 1 or 3/4 ...
>
> Have anybody any suggestion on how to achieve that ?
>  (with all pov-object, of course, not only the box). Post a reply to this message
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|  |  | More in p.b.i
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|  |  | "J. Grimbert" wrote:
> 
> I would like to use pov to render a view like the
> own drawn below for a box
> 
>   +--+
>  /  /|
> +--+ |
> |  | +
> |  |/
> +--+
> 
> It's just the classical 3D technical drawing...
> It looks like the orthographic camera, but
> increase of the z is transformed as p*(x+y),
> with p either 1/2, 1 or 3/4 ...
> 
> Have anybody any suggestion on how to achieve that ?
>  (with all pov-object, of course, not only the box).
Hmm. I can't think of a simple way but _a_ way is to apply a shear
operation to each object at the origin and then translate into position.
Cheers, PoD.
 Post a reply to this message
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|  |  | PoD <pod### [at] merlin net  au> schreef in berichtnieuws
37D### [at] merlin  net  au...
> Hmm. I can't think of a simple way but _a_ way is to apply a shear
> operation to each object at the origin and then translate into
position.
>
> Cheers, PoD.
Or shear the camera?
Ingo Post a reply to this message
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|  |  | Bob Hughes wrote:
> 
>  Also I flunked out of being a
> "advanced-user" so I probably shouldn't even be here.
>  ; b
> 
> Bob
Come on Bob, why don't we propose a group for the "disadvantaged user" or
something like that?
Remco
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|  |  | Please see p.b.i for a post called "Is this cabinet view?"
Peter Popov
ICQ: 15002700
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|  |  | Hmmm, yeah.... why not? <jest>
Bob
Remco de Korte <rem### [at] xs4all nl> wrote in message
news:37D4143C.5F635209@xs4all.nl...
> Bob Hughes wrote:
> >
> >  Also I flunked out of being a
> > "advanced-user" so I probably shouldn't even be here.
> >  ; b
> >
> > Bob
>
> Come on Bob, why don't we propose a group for the "disadvantaged
user" or
> something like that?
>
> Remco Post a reply to this message
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|  |  | ingo wrote:
> 
> PoD <pod### [at] merlin net  au> schreef in berichtnieuws
> 37D### [at] merlin  net  au...
> > Hmm. I can't think of a simple way but _a_ way is to apply a shear
> > operation to each object at the origin and then translate into
> position.
> >
> > Cheers, PoD.
> 
> Or shear the camera?
> 
> Ingo
That should work but I wouldn't know how to get it lined up right :( Post a reply to this message
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|  |  | PoD <pod### [at] merlin net  au> schreef in berichtnieuws >
>That should work but I wouldn't know how to get it lined up right :(
Something like this:
// Use -uv on commandline
#version 3.1;
global_settings {assumed_gamma 1.0}
light_source {<500, 500,-500>,1}
#declare Shear= transform {
   matrix <  1,  0,  0,
             0,  1,  0,
            .5,  0,  1,
             0,  0,  0 >
}
camera {
  location  <0.0, 0.5,-2.5>
  look_at   <0.0, 0.5, 0.0>
  angle 65
  transform Shear
}
box {
  <-0.5,0,-0.5>,<0.5,1,0.5>
  pigment {rgb 1}
} Post a reply to this message
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