Hi!
There is nurbs-curve with four control points.
For an example: (1,1.5,0.5),(0.5,0.5,1.2),(-0.8,-1,0.3),(-2,0.1,0.8)
It is necessary to create a tube along a curve, using two bicubic patches
Radius tube = R
The mathematics is necessary :) :) :)

Post a reply to this message

Am 22.02.2015 um 14:07 schrieb LanuHum:
> Hi!
> There is nurbs-curve with four control points.
> For an example: (1,1.5,0.5),(0.5,0.5,1.2),(-0.8,-1,0.3),(-2,0.1,0.8)
> It is necessary to create a tube along a curve, using two bicubic patches
> Radius tube = R
> The mathematics is necessary :) :) :)

Note that the mathematics say that strictly speaking this is impossible: 
With bicubic patches you can neither create a tube with perfectly 
circular cross-section (because a cubic spline in 2d space never forms a 
perfect circular arc), nor can you use them for any curved tubular 
structure with constant cross-section (because the parallel curve of a 
cubic spline in 2d space is never another cubic spline unless they both 
are linear).

Post a reply to this message

clipka <ano### [at] anonymousorg> wrote:
> Am 22.02.2015 um 14:07 schrieb LanuHum:
> > Hi!
> > There is nurbs-curve with four control points.
> > For an example: (1,1.5,0.5),(0.5,0.5,1.2),(-0.8,-1,0.3),(-2,0.1,0.8)
> > It is necessary to create a tube along a curve, using two bicubic patches
> > Radius tube = R
> > The mathematics is necessary :) :) :)
>
> Note that the mathematics say that strictly speaking this is impossible:
> With bicubic patches you can neither create a tube with perfectly
> circular cross-section (because a cubic spline in 2d space never forms a
> perfect circular arc), nor can you use them for any curved tubular
> structure with constant cross-section (because the parallel curve of a
> cubic spline in 2d space is never another cubic spline unless they both
> are linear).

Not necessarily. Approximate.
I am going to use rectangular triangles for calculation
But, I don't know how it is effective.
Therefore asked masters.

Post a reply to this message