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Here are the L*C*h(uv) functions I created. How do I turn them into
pigments?
Mike
Post a reply to this message
Attachments:
Download 'cielch_color_solid_cylinder_iso.pov.txt' (5 KB)
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Mike Horvath <mik### [at] gmail com> wrote:
> Here are the L*C*h(uv) functions I created. How do I turn them into
> pigments?
>
> Mike
http://www.povray.org/documentation/view/3.6.1/378/
?
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On 11/21/2016 3:02 PM, Bald Eagle wrote:
> Mike Horvath <mik### [at] gmailcom> wrote:
>> Here are the L*C*h(uv) functions I created. How do I turn them into
>> pigments?
>>
>> Mike
>
> http://www.povray.org/documentation/view/3.6.1/378/
> ?
>
I have three separate functions for R, G and B.
#declare convertLCH2RGB_R = function(L,C,H)
{correctRGB1(funcXYZ2RGBb1(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb2(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb3(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))))}
#declare convertLCH2RGB_G = function(L,C,H)
{correctRGB2(funcXYZ2RGBb1(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb2(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb3(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))))}
#declare convertLCH2RGB_B = function(L,C,H)
{correctRGB3(funcXYZ2RGBb1(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb2(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb3(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))))}
Actually, I can create a pigment already. But I don't know how to use
the functions in a isosurface or a parametric to make the 3D object the
pigment gets applied to, if possible.
Mike
Post a reply to this message
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Mike,
FYI:
you define
#local VRGB = <funcXYZ2RGBb1(VXYZ.x,VXYZ.y,VXYZ.z),
funcXYZ2RGBb2(VXYZ.x,VXYZ.y,VXYZ.z), funcXYZ2RGBb3(VXYZ.x,VXYZ.y,VXYZ.z)>;
and then (re)define the same variable in the very next line:
#local VRGB = <funcRGB2RGBa1(VRGB.x,VRGB.y,VRGB.z),
funcRGB2RGBa2(VRGB.x,VRGB.y,VRGB.z), funcRGB2RGBa3(VRGB.x,VRGB.y,VRGB.z)>;
Post a reply to this message
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On 11/21/2016 3:13 PM, Bald Eagle wrote:
> Mike,
>
> FYI:
>
> you define
> #local VRGB = <funcXYZ2RGBb1(VXYZ.x,VXYZ.y,VXYZ.z),
> funcXYZ2RGBb2(VXYZ.x,VXYZ.y,VXYZ.z), funcXYZ2RGBb3(VXYZ.x,VXYZ.y,VXYZ.z)>;
>
> and then (re)define the same variable in the very next line:
> #local VRGB = <funcRGB2RGBa1(VRGB.x,VRGB.y,VRGB.z),
> funcRGB2RGBa2(VRGB.x,VRGB.y,VRGB.z), funcRGB2RGBa3(VRGB.x,VRGB.y,VRGB.z)>;
>
>
>
The second function takes RGB as input and outputs RGB as well, so I
didn't rename the variable. You can change the variable name if that
suits you.
Mike
Post a reply to this message
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On 11/21/2016 3:10 PM, Mike Horvath wrote:
> On 11/21/2016 3:02 PM, Bald Eagle wrote:
>> Mike Horvath <mik### [at] gmailcom> wrote:
>>> Here are the L*C*h(uv) functions I created. How do I turn them into
>>> pigments?
>>>
>>> Mike
>>
>> http://www.povray.org/documentation/view/3.6.1/378/
>> ?
>>
>
>
>
> I have three separate functions for R, G and B.
>
> #declare convertLCH2RGB_R = function(L,C,H)
>
{correctRGB1(funcXYZ2RGBb1(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb2(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb3(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))))}
>
> #declare convertLCH2RGB_G = function(L,C,H)
>
{correctRGB2(funcXYZ2RGBb1(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb2(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb3(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))))}
>
> #declare convertLCH2RGB_B = function(L,C,H)
>
{correctRGB3(funcXYZ2RGBb1(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb2(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb3(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))))}
>
>
> Actually, I can create a pigment already. But I don't know how to use
> the functions in a isosurface or a parametric to make the 3D object the
> pigment gets applied to, if possible.
>
> Mike
Oops! You'll need to know these as well.
#declare correctRGB1 = function(R,G,B) {min(max(R,0),1)}
#declare correctRGB2 = function(R,G,B) {min(max(G,0),1)}
#declare correctRGB3 = function(R,G,B) {min(max(B,0),1)}
Post a reply to this message
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On 11/21/2016 3:29 PM, Mike Horvath wrote:
> On 11/21/2016 3:10 PM, Mike Horvath wrote:
>> On 11/21/2016 3:02 PM, Bald Eagle wrote:
>>> Mike Horvath <mik### [at] gmailcom> wrote:
>>>> Here are the L*C*h(uv) functions I created. How do I turn them into
>>>> pigments?
>>>>
>>>> Mike
>>>
>>> http://www.povray.org/documentation/view/3.6.1/378/
>>> ?
>>>
>>
>>
>>
>> I have three separate functions for R, G and B.
>>
>> #declare convertLCH2RGB_R = function(L,C,H)
>>
{correctRGB1(funcXYZ2RGBb1(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb2(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb3(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))))}
>>
>>
>> #declare convertLCH2RGB_G = function(L,C,H)
>>
{correctRGB2(funcXYZ2RGBb1(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb2(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb3(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))))}
>>
>>
>> #declare convertLCH2RGB_B = function(L,C,H)
>>
{correctRGB3(funcXYZ2RGBb1(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb2(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))),funcXYZ2RGBb3(funcLAB2XYZb1(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb2(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H)),funcLAB2XYZb3(funcLCH2LABa1(L,C,H),funcLCH2LABa2(L,C,H),funcLCH2LABa3(L,C,H))))}
>>
>>
>>
>> Actually, I can create a pigment already. But I don't know how to use
>> the functions in a isosurface or a parametric to make the 3D object the
>> pigment gets applied to, if possible.
>>
>> Mike
>
> Oops! You'll need to know these as well.
>
> #declare correctRGB1 = function(R,G,B) {min(max(R,0),1)}
> #declare correctRGB2 = function(R,G,B) {min(max(G,0),1)}
> #declare correctRGB3 = function(R,G,B) {min(max(B,0),1)}
>
>
That is wrong. The RGB values should *not* be corrected. In fact, if any
of R, G or B are outside the range of 0 to 1, then the coordinate/color
should be discarded. Sorry!
Mike
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Am 21.11.2016 um 21:56 schrieb Mike Horvath:
>>> Actually, I can create a pigment already. But I don't know how to use
>>> the functions in a isosurface or a parametric to make the 3D object the
>>> pigment gets applied to, if possible.
>>>
>>> Mike
>>
>> Oops! You'll need to know these as well.
>>
>> #declare correctRGB1 = function(R,G,B) {min(max(R,0),1)}
>> #declare correctRGB2 = function(R,G,B) {min(max(G,0),1)}
>> #declare correctRGB3 = function(R,G,B) {min(max(B,0),1)}
>>
>>
>
> That is wrong. The RGB values should *not* be corrected. In fact, if any
> of R, G or B are outside the range of 0 to 1, then the coordinate/color
> should be discarded. Sorry!
So if I understand you correctly, the shape you want is exactly the
volume for which R, G and B are all within the range from 0 to 1.
That sounds like a job for an isosurface to me.
Variant A: Create six isosurfaces, each representing one of the
boundaries (R<0, G<0, B<0, R>1, G>1, B>1), and intersect them.
Variant B: Refactor the functions from variant A, so that they have the
same threshold, combine them using max() or min() to achieve the
intersection effect, and turn that into a single isosurface.
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On 11/21/2016 4:23 PM, clipka wrote:
> Am 21.11.2016 um 21:56 schrieb Mike Horvath:
>
>>>> Actually, I can create a pigment already. But I don't know how to use
>>>> the functions in a isosurface or a parametric to make the 3D object the
>>>> pigment gets applied to, if possible.
>>>>
>>>> Mike
>>>
>>> Oops! You'll need to know these as well.
>>>
>>> #declare correctRGB1 = function(R,G,B) {min(max(R,0),1)}
>>> #declare correctRGB2 = function(R,G,B) {min(max(G,0),1)}
>>> #declare correctRGB3 = function(R,G,B) {min(max(B,0),1)}
>>>
>>>
>>
>> That is wrong. The RGB values should *not* be corrected. In fact, if any
>> of R, G or B are outside the range of 0 to 1, then the coordinate/color
>> should be discarded. Sorry!
>
> So if I understand you correctly, the shape you want is exactly the
> volume for which R, G and B are all within the range from 0 to 1.
>
Yes, exactly!
> That sounds like a job for an isosurface to me.
>
> Variant A: Create six isosurfaces, each representing one of the
> boundaries (R<0, G<0, B<0, R>1, G>1, B>1), and intersect them.
>
> Variant B: Refactor the functions from variant A, so that they have the
> same threshold, combine them using max() or min() to achieve the
> intersection effect, and turn that into a single isosurface.
>
I don't know how to do either variant. :(
Mike
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On 11/21/2016 9:33 PM, Mike Horvath wrote:
>> Variant B: Refactor the functions from variant A, so that they have the
>> same threshold,
How to cook a haggis:
First catch your Haggis then...
>
> I don't know how to do either variant. :(
Don't ya just love it when someone says "Simply..." ;)
--
Regards
Stephen
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On 11/21/2016 4:33 PM, Mike Horvath wrote:
> On 11/21/2016 4:23 PM, clipka wrote:
>>
>> So if I understand you correctly, the shape you want is exactly the
>> volume for which R, G and B are all within the range from 0 to 1.
>>
>
> Yes, exactly!
>
>
>> That sounds like a job for an isosurface to me.
>>
>> Variant A: Create six isosurfaces, each representing one of the
>> boundaries (R<0, G<0, B<0, R>1, G>1, B>1), and intersect them.
>>
>> Variant B: Refactor the functions from variant A, so that they have the
>> same threshold, combine them using max() or min() to achieve the
>> intersection effect, and turn that into a single isosurface.
>>
>
> I don't know how to do either variant. :(
>
> Mike
Forgot to add that I want to use polar coordinates (if that makes a
difference).
Mike
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On 11/21/2016 4:23 PM, clipka wrote:
> Am 21.11.2016 um 21:56 schrieb Mike Horvath:
>
>>>> Actually, I can create a pigment already. But I don't know how to use
>>>> the functions in a isosurface or a parametric to make the 3D object the
>>>> pigment gets applied to, if possible.
>>>>
>>>> Mike
>>>
>>> Oops! You'll need to know these as well.
>>>
>>> #declare correctRGB1 = function(R,G,B) {min(max(R,0),1)}
>>> #declare correctRGB2 = function(R,G,B) {min(max(G,0),1)}
>>> #declare correctRGB3 = function(R,G,B) {min(max(B,0),1)}
>>>
>>>
>>
>> That is wrong. The RGB values should *not* be corrected. In fact, if any
>> of R, G or B are outside the range of 0 to 1, then the coordinate/color
>> should be discarded. Sorry!
>
> So if I understand you correctly, the shape you want is exactly the
> volume for which R, G and B are all within the range from 0 to 1.
>
> That sounds like a job for an isosurface to me.
>
> Variant A: Create six isosurfaces, each representing one of the
> boundaries (R<0, G<0, B<0, R>1, G>1, B>1), and intersect them.
>
> Variant B: Refactor the functions from variant A, so that they have the
> same threshold, combine them using max() or min() to achieve the
> intersection effect, and turn that into a single isosurface.
>
I am trying random things now.
isosurface
{
function {max(convertLCH2RGB_R(x,y,z), 1)}
contained_by
{
box {-2,+2}
}
// threshold FLOAT_VALUE
accuracy 0.01
max_gradient 5
// [evaluate P0, P1, P2]
// open
// [max_trace INTEGER] | [all_intersections]
pigment {rgb 1}
}
This takes a long time to render, but there's nothing visible happening.
Mike
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I tried this as well.
parametric
{
function { convertLCH2RGB_R(u,100,v) }
function { convertLCH2RGB_G(u,100,v) }
function { convertLCH2RGB_B(u,100,v) }
<0,0>, <100,360>
contained_by
{
box {-2,+2}
}
max_gradient 5
accuracy 0.01
precompute 10 x,y,z
pigment {rgb 1}
}
The render is too slow. The pps is below 100 and still dropping.
Mike
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Am 22.11.2016 um 01:46 schrieb Mike Horvath:
> I am trying random things now.
>
> isosurface
> {
> function {max(convertLCH2RGB_R(x,y,z), 1)}
throw away the max() function, and take care of the polar-ish coordinate
system by replacing:
convertLCH2RGB_R(x,y,z)
with:
convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x/z)*pi/180)
(presuming you want L up and I got the math right)
> contained_by
> {
> box {-2,+2}
> }
> // threshold FLOAT_VALUE
... and use threshold 1. That should give you something visible.
> accuracy 0.01
> max_gradient 5
> // [evaluate P0, P1, P2]
> // open
> // [max_trace INTEGER] | [all_intersections]
> pigment {rgb 1}
> }
>
> This takes a long time to render, but there's nothing visible happening.
>
> Mike
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On 11/22/2016 2:30 AM, clipka wrote:
> Am 22.11.2016 um 01:46 schrieb Mike Horvath:
>
>> I am trying random things now.
>>
>> isosurface
>> {
>> function {max(convertLCH2RGB_R(x,y,z), 1)}
>
> throw away the max() function, and take care of the polar-ish coordinate
> system by replacing:
>
> convertLCH2RGB_R(x,y,z)
>
> with:
>
> convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x/z)*pi/180)
>
> (presuming you want L up and I got the math right)
>
>> contained_by
>> {
>> box {-2,+2}
>> }
>> // threshold FLOAT_VALUE
>
> ... and use threshold 1. That should give you something visible.
>
>> accuracy 0.01
>> max_gradient 5
>> // [evaluate P0, P1, P2]
>> // open
>> // [max_trace INTEGER] | [all_intersections]
>> pigment {rgb 1}
>> }
>>
>> This takes a long time to render, but there's nothing visible happening.
>>
>> Mike
>
THANK YOU!!
However atan2 requires two parameters and your math only has one.
Mike
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Am 22.11.2016 um 08:33 schrieb Mike Horvath:
>> convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x/z)*pi/180)
> THANK YOU!!
>
> However atan2 requires two parameters and your math only has one.
Sorry, try atan2(x,z).
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On 11/22/2016 2:44 AM, clipka wrote:
> Am 22.11.2016 um 08:33 schrieb Mike Horvath:
>
>>> convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x/z)*pi/180)
>
>> THANK YOU!!
>>
>> However atan2 requires two parameters and your math only has one.
>
> Sorry, try atan2(x,z).
>
Here is the whole file again with your changes. The shape I get when I
render is that of a pointy cap. I don't know if that's correct or not.
Mike
Post a reply to this message
Attachments:
Download 'utf-8' (7 KB)
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Am 22.11.2016 um 08:45 schrieb Mike Horvath:
> On 11/22/2016 2:44 AM, clipka wrote:
>> Am 22.11.2016 um 08:33 schrieb Mike Horvath:
>>
>>>> convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x/z)*pi/180)
>>
>>> THANK YOU!!
>>>
>>> However atan2 requires two parameters and your math only has one.
>>
>> Sorry, try atan2(x,z).
>>
>
> Here is the whole file again with your changes. The shape I get when I
> render is that of a pointy cap. I don't know if that's correct or not.
How would I know -- I'm not familiar with that colour model.
Now you need to intersect that shape with the five others -- or use the
combined function:
min(
convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
1-convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
1-convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
1-convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180)
)
should do the job, I think.
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On 11/22/2016 3:31 AM, clipka wrote:
> min(
> convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> 1-convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> 1-convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> 1-convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180)
> )
I think the last parameter should be atan2(x,z)*180/pi because atan2
returns radians and convertLCH2RGB_R expects degrees.
Also, here's a rough approximation of what the surface should look like.
https://commons.wikimedia.org/wiki/File:Cielch_color_solid_cylinder.png
But with smooth curves instead of blocky sections.
Mike
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On 11/22/2016 3:31 AM, clipka wrote:
> min(
> convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> 1-convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> 1-convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> 1-convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180)
> )
Forgot to say that the above just results in a cube.
Mike
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Am 22.11.2016 um 09:43 schrieb Mike Horvath:
> On 11/22/2016 3:31 AM, clipka wrote:
>> min(
>> convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>> convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>> convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>> 1-convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>> 1-convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>> 1-convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180)
>> )
>
> I think the last parameter should be atan2(x,z)*180/pi because atan2
> returns radians and convertLCH2RGB_R expects degrees.
I guess you're right about this one.
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On 11/22/2016 4:44 AM, clipka wrote:
> Am 22.11.2016 um 09:43 schrieb Mike Horvath:
>> On 11/22/2016 3:31 AM, clipka wrote:
>>> min(
>>> convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>>> convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>>> convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>>> 1-convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>>> 1-convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>>> 1-convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180)
>>> )
>>
>> I think the last parameter should be atan2(x,z)*180/pi because atan2
>> returns radians and convertLCH2RGB_R expects degrees.
>
> I guess you're right about this one.
>
I am also not sure if using atan2 is good, since that only covers 90
degrees, whereas the hue circle must use all 360 degrees.
Mike
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On 11/22/2016 7:59 PM, Mike Horvath wrote:
> On 11/22/2016 4:44 AM, clipka wrote:
>> Am 22.11.2016 um 09:43 schrieb Mike Horvath:
>>> On 11/22/2016 3:31 AM, clipka wrote:
>>>> min(
>>>> convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>>>> convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>>>> convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>>>>
>>>> 1-convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>>>>
>>>> 1-convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
>>>> 1-convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180)
>>>> )
>>>
>>> I think the last parameter should be atan2(x,z)*180/pi because atan2
>>> returns radians and convertLCH2RGB_R expects degrees.
>>
>> I guess you're right about this one.
>>
>
> I am also not sure if using atan2 is good, since that only covers 90
> degrees, whereas the hue circle must use all 360 degrees.
>
> Mike
Sorry. Disregard that. It works.
Mike
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Am 23.11.2016 um 02:11 schrieb Mike Horvath:
>> I am also not sure if using atan2 is good, since that only covers 90
>> degrees, whereas the hue circle must use all 360 degrees.
>>
>> Mike
>
> Sorry. Disregard that. It works.
That's the fun thing about `atan2(a,b)`: In contrast to `atan(a/b)` it
doesn't lose the information about the quadrant; it also avoids the
singularity at b=0 (provided a<>0).
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On 11/22/2016 3:31 AM, clipka wrote:
>> Here is the whole file again with your changes. The shape I get when I
>> render is that of a pointy cap. I don't know if that's correct or not.
>
> How would I know -- I'm not familiar with that colour model.
>
> Now you need to intersect that shape with the five others -- or use the
> combined function:
>
> min(
> convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> 1-convertLCH2RGB_R(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> 1-convertLCH2RGB_G(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180),
> 1-convertLCH2RGB_B(y*200-100,sqrt(x*x+z*z)*100,atan2(x,z)*pi/180)
> )
>
> should do the job, I think.
>
Using "min" all I got was a cube. Switching to "max" instead, I got a
shape... of some sort. I'm not sure it's the correct one. Check the
thread in p.b.i and tell me if the images show the same object.
http://news.povray.org/583548b6%40news.povray.org
Mike
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I've attached the latest version of the script.
Mike
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Attachments:
Download 'cielch_color_solid_cylinder_isosurface.pov.txt' (9 KB)
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