Hi all,

I've done this arrow:
======================================
union {
cone { <0,0,0>,2,<3,0,0>,0  }
cylinder  { <-5,0,0>,<0,0,0>,1 }
pigment { color  Gray*1.2   }
scale <3, 1.6, 1>
scale 0.5
rotate <0, 0, -90>
}
======================================
Now I was thinking how can I turn the cylinder like a bridge.

I thought that using a spline would work, but I'm not sure if it's the
easiest way, because I think should be another easier way to turn the
cylinder 90º for exemple.

Using this:

#local yPos = Ampl*sin(xFreq*xCnt/xNr*2*pi)*cos(zFreq*zCnt/zNr*2*pi);

and then declaring:

#declare Amplitude = 30;

to make the arch.

Any ideas?

Thanks in advance,
Oleguer

Post a reply to this message

> Now I was thinking how can I turn the cylinder like a bridge.

Will a segment of a torus do? You can intersect a torus with two planes to
get a small piece of it.

 - Slime
 [ http://www.slimeland.com/ ]

Post a reply to this message

Yeah, good idea Slime! I haven't thought it.

But, should be a way to turn the cylinder like a half torus and I don't know 
how can I do it.

Best regards,
Oleguer


"Slime" <fak### [at] emailaddress> escribió en el mensaje 
news:42e0d4a1$1@news.povray.org...
>> Now I was thinking how can I turn the cylinder like a bridge.
>
> Will a segment of a torus do? You can intersect a torus with two planes to
> get a small piece of it.
>
> - Slime
> [ http://www.slimeland.com/ ]
>
>

Post a reply to this message

Investiga con matrix keyword, tal vez no sea exactamente lo que buscas, pero
es lo que más se aproxima.
http://enphilistor.users4.50megs.com/matrix.htm

--
light_source{0,1}#macro C(r,p)cylinder{x*-2,x*2,.9 pigment { rgb
p} /* B Gimeno estoeslarealidad */ rotate p*90 } #end difference
{box {-1,1} C(z /* http://usuarios.lycos.es/game2413 */,x)C(x,y)
C(z,z) pigment{rgb 2} rotate 45 translate z*4} // www.povray.org

Post a reply to this message

> But, should be a way to turn the cylinder like a half torus and I don't
know
> how can I do it.

I'm not quite sure what you're asking if my reply didn't answer it.

Let's say you had a cylinder, along the Y axis from <0,0,0> to <0,H,0> with
radius R. You want to curl the cylinder by X degrees towards the x-axis. You
could do it like this:

#declare H = 2;
#declare X = 90;
#declare R = .2;

intersection {
    torus {
        // we want X/360 * circumference of torus to equal H
        #declare MajorRad = H*360/(X*2*pi);
        MajorRad,
        // minor radius = cylinder's radius
        R

    }

    #if (X < 180)
        intersection {
    #else
        union {
    #end
        // cut off the bottom
        plane {
            -z,0
        }
        // cut off the other end
        plane {
            z,0
            rotate X*y
        }
    }

    translate MajorRad*x
    rotate -90*x

    pigment {rgb 1}

    rotate 90*x
}

It sounds like you want X = 180 if you want "half a torus." Watch what
happens as you bring X from 0 to 90, 180 and even up to 360.

 - Slime
 [ http://www.slimeland.com/ ]

Post a reply to this message

B. Gimeno <NO_### [at] lycoses> wrote:
> Investiga con matrix keyword, tal vez no sea exactamente lo que buscas, pero
> es lo que más se aproxima.
> http://enphilistor.users4.50megs.com/matrix.htm

  Matrix transformations can only perform linear transformations. They
can't bend a cylinder into a torus segment.

-- 
Hanki elämä, hanki Linux.
                                                          - Warp

Post a reply to this message

Hi all,

Yeah, you've used a torus to do it.

Sorry for the late reply, I was outside of Lleida.

Thanks,
Oleguer




"Slime" <fak### [at] emailaddress> escribió en el mensaje 
news:42e2ca2c$1@news.povray.org...
>> But, should be a way to turn the cylinder like a half torus and I don't
> know
>> how can I do it.
>
> I'm not quite sure what you're asking if my reply didn't answer it.
>
> Let's say you had a cylinder, along the Y axis from <0,0,0> to <0,H,0> 
> with
> radius R. You want to curl the cylinder by X degrees towards the x-axis. 
> You
> could do it like this:
>
> #declare H = 2;
> #declare X = 90;
> #declare R = .2;
>
> intersection {
>    torus {
>        // we want X/360 * circumference of torus to equal H
>        #declare MajorRad = H*360/(X*2*pi);
>        MajorRad,
>        // minor radius = cylinder's radius
>        R
>
>    }
>
>    #if (X < 180)
>        intersection {
>    #else
>        union {
>    #end
>        // cut off the bottom
>        plane {
>            -z,0
>        }
>        // cut off the other end
>        plane {
>            z,0
>            rotate X*y
>        }
>    }
>
>    translate MajorRad*x
>    rotate -90*x
>
>    pigment {rgb 1}
>
>    rotate 90*x
> }
>
> It sounds like you want X = 180 if you want "half a torus." Watch what
> happens as you bring X from 0 to 90, 180 and even up to 360.
>
> - Slime
> [ http://www.slimeland.com/ ]
>
>

Post a reply to this message

Hi Bruno,

Thanks for the page. I will read it, it looks interesting.

Regards,
Oleguer


"B. Gimeno" <NO_### [at] lycoses> escribió en el mensaje 
news:42e2be48$1@news.povray.org...
> Investiga con matrix keyword, tal vez no sea exactamente lo que buscas, 
> pero
> es lo que más se aproxima.
> http://enphilistor.users4.50megs.com/matrix.htm
>
> --
> light_source{0,1}#macro C(r,p)cylinder{x*-2,x*2,.9 pigment { rgb
> p} /* B Gimeno estoeslarealidad */ rotate p*90 } #end difference
> {box {-1,1} C(z /* http://usuarios.lycos.es/game2413 */,x)C(x,y)
> C(z,z) pigment{rgb 2} rotate 45 translate z*4} // www.povray.org
>
>

Post a reply to this message

Hi Slime and all,

Using your code like this:
======================================
#declare H = 2;
#declare X = 90;
#declare R = .2;

#declare Fletxa = object {
intersection {
torus {
// we want X/360 * circumference of torus to equal H
#declare MajorRad = H*360/(X*2*pi);
MajorRad,
// minor radius = cylinder's radius
R }
#if (X < 180)
intersection {
#else

union {
#end
// cut off the bottom
plane { -z, 0 }
// cut off the other end
plane { z, 0
rotate X*y } }

translate MajorRad*x
rotate -90*x
pigment { rgb 1 }
rotate 90*x
translate <0, 0, 0> + Direction
}}

#declare Punta = object {
cone { <0,0,0>,0.5,<1.5,0,0>,0
pigment { rgb 1 } }
scale 0.5
translate <0, 6, 0> + Direction
}

union {
object { Fletxa }
object { Punta rotate <0, 90, 0> } }
======================================
How can I calculate the position of the cone the place it exactly on the end 
of the torus?

Regards,
Oleguer


"Oleguer Vilella" <ole### [at] infonegociocom> escribió en el mensaje 
news:42ebcc73@news.povray.org...
> Hi all,
>
> Yeah, you've used a torus to do it.
>
> Sorry for the late reply, I was outside of Lleida.
>
> Thanks,
> Oleguer
>
>
>
>
> "Slime" <fak### [at] emailaddress> escribió en el mensaje 
> news:42e2ca2c$1@news.povray.org...
>>> But, should be a way to turn the cylinder like a half torus and I don't
>> know
>>> how can I do it.
>>
>> I'm not quite sure what you're asking if my reply didn't answer it.
>>
>> Let's say you had a cylinder, along the Y axis from <0,0,0> to <0,H,0> 
>> with
>> radius R. You want to curl the cylinder by X degrees towards the x-axis. 
>> You
>> could do it like this:
>>
>> #declare H = 2;
>> #declare X = 90;
>> #declare R = .2;
>>
>> intersection {
>>    torus {
>>        // we want X/360 * circumference of torus to equal H
>>        #declare MajorRad = H*360/(X*2*pi);
>>        MajorRad,
>>        // minor radius = cylinder's radius
>>        R
>>
>>    }
>>
>>    #if (X < 180)
>>        intersection {
>>    #else
>>        union {
>>    #end
>>        // cut off the bottom
>>        plane {
>>            -z,0
>>        }
>>        // cut off the other end
>>        plane {
>>            z,0
>>            rotate X*y
>>        }
>>    }
>>
>>    translate MajorRad*x
>>    rotate -90*x
>>
>>    pigment {rgb 1}
>>
>>    rotate 90*x
>> }
>>
>> It sounds like you want X = 180 if you want "half a torus." Watch what
>> happens as you bring X from 0 to 90, 180 and even up to 360.
>>
>> - Slime
>> [ http://www.slimeland.com/ ]
>>
>>
>
>

Post a reply to this message

If I do this:
======================================
#declare H = 2;
#declare X = 90;
#declare R = .2;
#declare Fletxa = object {
intersection {
torus {
// we want X/360 * circumference of torus to equal H
#declare MajorRad = H*360/(X*2*pi);
MajorRad,
// minor radius = cylinder's radius
R }
#if (X < 180)
intersection {
#else

union {
#end
// cut off the bottom
plane { -z, 0 }
// cut off the other end
plane { z, 0
rotate X*y } }

translate MajorRad*x
rotate -90*x
pigment { rgb 1 }
rotate 90*x
translate <1.06, -0.7, 0> + Direction*3
rotate <180, 0, 0>
}}

#declare Punta = object {
cone { <0,0,0>,0.5,<1.5,0,0>,0
pigment { rgb 1 } }
scale 0.5
translate <1.5, 3, 0> + Direction*3
rotate <0, 180, 180>
}


union {
object { Fletxa }
object { Punta }
translate <6, 0, 0> + Direction }
======================================
When I translate all the union, the cylinder isn't moving following the 
torus. Why? They are into an union, so, the translate vector should move all 
the object. Isn't it?

Regards,
Oleguer



"Oleguer Vilella" <ole### [at] infonegociocom> escribió en el mensaje 
news:42edea9c@news.povray.org...
> Hi Slime and all,
>
> Using your code like this:
> ======================================
> #declare H = 2;
> #declare X = 90;
> #declare R = .2;
>
> #declare Fletxa = object {
> intersection {
> torus {
> // we want X/360 * circumference of torus to equal H
> #declare MajorRad = H*360/(X*2*pi);
> MajorRad,
> // minor radius = cylinder's radius
> R }
> #if (X < 180)
> intersection {
> #else
>
> union {
> #end
> // cut off the bottom
> plane { -z, 0 }
> // cut off the other end
> plane { z, 0
> rotate X*y } }
>
> translate MajorRad*x
> rotate -90*x
> pigment { rgb 1 }
> rotate 90*x
> translate <0, 0, 0> + Direction
> }}
>
> #declare Punta = object {
> cone { <0,0,0>,0.5,<1.5,0,0>,0
> pigment { rgb 1 } }
> scale 0.5
> translate <0, 6, 0> + Direction
> }
>
> union {
> object { Fletxa }
> object { Punta rotate <0, 90, 0> } }
> ======================================
> How can I calculate the position of the cone the place it exactly on the 
> end of the torus?
>
> Regards,
> Oleguer
>
>
> "Oleguer Vilella" <ole### [at] infonegociocom> escribió en el mensaje 
> news:42ebcc73@news.povray.org...
>> Hi all,
>>
>> Yeah, you've used a torus to do it.
>>
>> Sorry for the late reply, I was outside of Lleida.
>>
>> Thanks,
>> Oleguer
>>
>>
>>
>>
>> "Slime" <fak### [at] emailaddress> escribió en el mensaje 
>> news:42e2ca2c$1@news.povray.org...
>>>> But, should be a way to turn the cylinder like a half torus and I don't
>>> know
>>>> how can I do it.
>>>
>>> I'm not quite sure what you're asking if my reply didn't answer it.
>>>
>>> Let's say you had a cylinder, along the Y axis from <0,0,0> to <0,H,0> 
>>> with
>>> radius R. You want to curl the cylinder by X degrees towards the x-axis. 
>>> You
>>> could do it like this:
>>>
>>> #declare H = 2;
>>> #declare X = 90;
>>> #declare R = .2;
>>>
>>> intersection {
>>>    torus {
>>>        // we want X/360 * circumference of torus to equal H
>>>        #declare MajorRad = H*360/(X*2*pi);
>>>        MajorRad,
>>>        // minor radius = cylinder's radius
>>>        R
>>>
>>>    }
>>>
>>>    #if (X < 180)
>>>        intersection {
>>>    #else
>>>        union {
>>>    #end
>>>        // cut off the bottom
>>>        plane {
>>>            -z,0
>>>        }
>>>        // cut off the other end
>>>        plane {
>>>            z,0
>>>            rotate X*y
>>>        }
>>>    }
>>>
>>>    translate MajorRad*x
>>>    rotate -90*x
>>>
>>>    pigment {rgb 1}
>>>
>>>    rotate 90*x
>>> }
>>>
>>> It sounds like you want X = 180 if you want "half a torus." Watch what
>>> happens as you bring X from 0 to 90, 180 and even up to 360.
>>>
>>> - Slime
>>> [ http://www.slimeland.com/ ]
>>>
>>>
>>
>>
>
>

Post a reply to this message