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If this were 2D it would be easy for me, but it isn't 2D and this is
making me use up my scratch paper to no purpose...
If you have a line (line segment? maybe) with a known length, starting
at a known set of coordinates, which is then rotated around those
coordinates by arbitrary amounts around the x and z axes, how do you
calculate the coordinates of the other end of the line?
-Xplo
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From: Warp
Subject: Re: 3D trig hurt brain! (or, Another Stupid Math Question)
Date: 8 Apr 2002 19:57:02
Message: <3cb22e4e@news.povray.org>
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Xplo Eristotle <inq### [at] unforgettable com> wrote:
> If you have a line (line segment? maybe) with a known length, starting
> at a known set of coordinates, which is then rotated around those
> coordinates by arbitrary amounts around the x and z axes, how do you
> calculate the coordinates of the other end of the line?
With vrotate() ;)
--
#macro N(D)#if(D>99)cylinder{M()#local D=div(D,104);M().5,2pigment{rgb M()}}
N(D)#end#end#macro M()<mod(D,13)-6mod(div(D,13)8)-3,10>#end blob{
N(11117333955)N(4254934330)N(3900569407)N(7382340)N(3358)N(970)}// - Warp -
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From: Tor Olav Kristensen
Subject: Re: 3D trig hurt brain! (or, Another Stupid Math Question)
Date: 8 Apr 2002 19:59:19
Message: <3C895AE1.D33F8D61@online.no>
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Xplo Eristotle wrote:
>
> If this were 2D it would be easy for me, but it isn't 2D and this is
> making me use up my scratch paper to no purpose...
>
> If you have a line (line segment? maybe) with a known length, starting
> at a known set of coordinates, which is then rotated around those
> coordinates by arbitrary amounts around the x and z axes, how do you
> calculate the coordinates of the other end of the line?
Warning: Untested code below
The original "line":
cylinder { pA, pB, CylRad }
// Assuming that you wish the x-axis rotation
// to take place before the z-axis rotation:
#declare pNewB = pA + vrotate(pB - pA, <AngleX, 0 AngleZ>);
The rotated "line":
cylinder { pA, pNewB, CylRad }
Tor Olav
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Warp wrote:
>
> Xplo Eristotle <inq### [at] unforgettablecom> wrote:
> > If you have a line (line segment? maybe) with a known length, starting
> > at a known set of coordinates, which is then rotated around those
> > coordinates by arbitrary amounts around the x and z axes, how do you
> > calculate the coordinates of the other end of the line?
>
> With vrotate() ;)
Doh!!
Okay, thanks guys (note to self: RTFM again).
-Xplo
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From: Tor Olav Kristensen
Subject: Re: 3D trig hurt brain! (or, Another Stupid Math Question)
Date: 8 Apr 2002 20:09:49
Message: <3CB22DC7.B16EE501@online.no>
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Tor Olav Kristensen wrote:
>...
Sorry for the wrong date.
Tor Olav
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