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Assuming a threshold of 0, an isosurface with function { (x^2 + y^2 +
z^2) - n } should be the same size as sphere { <0, 0, 0>, n } -- is this
right or wrong?
-Xplo
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On Mon, 30 Apr 2001 13:30:13 -0700, Xplo Eristotle wrote:
>Assuming a threshold of 0, an isosurface with function { (x^2 + y^2 +
>z^2) - n } should be the same size as sphere { <0, 0, 0>, n } -- is this
>right or wrong?
Wrong. You want the 'n' in your iso function to be 'n^2'.
--
#local R=<7084844682857967,32787982,826975826580>#macro L(P)concat(#while(P)chr(
mod(P,100)),#local P=P/100;#end"")#end background{rgb 1}text{ttf L(R.x)L(R.y)0,0
translate<-.8,0,-1>}text{ttf L(R.x)L(R.z)0,0translate<-1.6,-.75,-1>}sphere{z/9e3
4/26/2001finish{reflection 1}}//ron.parker@povray.org My opinions, nobody else's
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Xplo Eristotle wrote:
>
> Assuming a threshold of 0, an isosurface with function { (x^2 + y^2 +
> z^2) - n } should be the same size as sphere { <0, 0, 0>, n } -- is this
> right or wrong?
>
> -Xplo
Wrong.
(x^2 + y^2 +z^2) - r^2 =0 is sphere's equation.
BTW, Your computer's time seems to be wrong...
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