Le_Forgeron <jgr### [at] freefr> wrote:
> The temporary buffer for 12800 x 9600 output is> sizeof(double)*5*dimensions (*) : that's 124F80000 bytes in hex, more> than can be represented on 32 bits.
I have one more question.
How can the value 5 in the formular be explained?
3 is quite easy to explain because of RGB. But why 5 ?
Is it because of an alpha channel?