On 9/10/21 11:26 AM, Kenneth wrote:
> William F Pokorny <ano### [at] anonymousorg> wrote:
>> [source code snippets]
>> The variation above works for me in all v3.7+ versions I have in hand.
> Just discovered that the following also produces the error and fails-- unless
> the #debug is there. Seems that in this case, the inner #end actually *needs*
> something to follow it! I tried adding #break and/or #end here and there
> (guesswork!) to try and MAKE it work without the #debug, but no luck so far.
> #declare R = seed(4711);
> #for (I, 1, 100)
> #if (rand(R) < 1.1) // always less than 1.1
> #break // terminate loop early
> // #debug concat(str(I,0,0), " iterations and counting\n")
Thanks! This example a stinker - my hack doesn't fix it. I don't
immediately see a way to handle this case. After the break it reads all
the way to through the last '#end' in both v3.8 beta 2 and my hacked
In other words, by the time it's done with the work to read to the end
of the block containing the break, the parser finds itself not inside
any nested block from which to break.
If the #debug is not commented, it stops there and breaks from the for
Added your test case to the others. Unsure when I might pick up looking
at it again.
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