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Assuming the red dot is the origin of the ray, going in the direction of the
first point (green) I want to find a point along the yellow line that is the
same distance from both points (Blue and Green).
--
Kevin
http://www.geocities.com/qsquared_1999/
#macro _(r)#if(r<12)#local i=asc(substr("oqshil
acefg",r,1))-97;disc{<mod(i,7)-3,div(i,7)-1,6>,z,.4
pigment{rgb 10}}_(r+1)#end#end _(1)//KL
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Attachments:
Download 'diagram.jpg' (6 KB)
Preview of image 'diagram.jpg'
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Simple- make a line from the blue to the green. Bisect it with a
perpendicular line. The point of intersection of the bisector and the yellow
line is equidistant from both blue and green.
Cheers!
Chip Shults
My robotics, space and CGI web page - http://home.cfl.rr.com/aichip
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"Sir Charles W. Shults III" <aic### [at] cfl rrcom> wrote in
news:3e18f947@news.povray.org:
> Simple- make a line from the blue to the green. Bisect it with a
> perpendicular line. The point of intersection of the bisector and the
> yellow line is equidistant from both blue and green.
Sometimes the simplest methods evade us, I learned something here...
---
(MIKA) Marc Champagne
marcch.AT.videotron.DOT.ca
Montreal, CANADA
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Sir Charles W. Shults III wrote:
> Simple- make a line from the blue to the green. Bisect it with a
> perpendicular line. The point of intersection of the bisector and the yellow
^^^^
> line is equidistant from both blue and green.
plane. ^_^
--
___ ______________________________________________
| \ |_ website: http://davidf.faricy.net/
|_/avid |ontaine email: <dav### [at] faricynet>
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No need to specify that- it all happens on a single plane anyway, every
time. The entire process is 2D.
Cheers!
Chip Shults
My robotics, space and CGI web page - http://home.cfl.rr.com/aichip
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