Hello,


That's exactly right.
In fact, the code is interpreted as #declare y0 = a * x0 * (+b);
That makes perfect sense.

Another problem with understanding the mechanism is that i used the 
actual values from my code. If i use simpler values, it becomes much 
clearer right away. First, with a = 1, we eliminate one parameter; then, 
with b = 2 and x0 = 3, we get y0 = 3 + 2 = 5 vs y0 = 3 * 2 = 6.




Tor, Leroy, thank you both very much for your suggestions.



-- 
klp
compagnie de la banquise

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