POV-Ray : Newsgroups : povray.general : Transforming matrix question : Re: Transforming matrix question Server Time
28 Jul 2024 22:26:56 EDT (-0400)
  Re: Transforming matrix question  
From: Louis
Date: 28 Dec 2013 11:45:03
Message: <web.52beff7e2d7d0efacbe7ea7c0@news.povray.org>
clipka <ano### [at] anonymousorg> wrote:
> Outside functions, "z" is a predefined vector constant evaluating to
> <0,0,1>; thus, "z.z" is the z-component of that vector, i.e. 1.
>
> Inside functions without an explicit parameter list, "z" is the third of
> three parameters, which in an isosurface object will be the z-coordinate
> of whatever point is currently being examined. Note that with function
> parameters always being scalars, "z.z" will generate a parse error when
> used inside such a function.

Thanks for clearing that up!


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