> You may look at isosurface. They are often faster than parametrics for
> the same actual shape. In your case, adding "open" should be preferable
> so that the container don't show.
>
> You may also look at the quadric.

Ah, okay I think I see where you're going here.  If you view a hyperbola as:

y^2-x^2 = 1 with z=0

then the surface "near" the hyperbola is:

(y^2-x^2-1)^2 + z^4 = 1/10 or any similar small constant on the right.

I could do this with an isosurface object, I guess with a 4th order polynomial.

I'm not seeing how a quadric would suffice.

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