"SharkD" <nomail@nomail> wrote:
> I've worked things out in excel so that all I need to do is find the equation of
> this curve:
>
> http://img266.imageshack.us/img266/4454/curvepo9.png
>
> Unfortunately, I can't figure out what kind of curve it is. It kind of looks
> like a catenary.
>
> -Mike

This curve (a catenary) seems to fit the points fairly closely:

f(x) = 0.2 cosh(x / 0.76) + 0.2

-Mike

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