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Darren New wrote:
>
> I have a manual for a clock. In the back is the troubleshooting chart.
>
> Q: No numbers appear on display.
> A: Insert fresh battery.
>
> Q: Numbers appear on display even without battery.
> A: Take sticker off of display.
>
:-)
--
I will be brief but not nearly so brief as Salvador Dali, who gave the
world's shortest speech. He said, "I will be so brief I am already
finished," then he sat down.
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Darren New wrote:
> Q: Numbers appear on display even without battery.
> A: Take sticker off of display.
You *know* this question came up in end-user testing! ;-)
[My manual appears to have been machine-translated form some other
language, judging by the strange sentence constructions...]
--
http://blog.orphi.me.uk/
http://www.zazzle.com/MathematicalOrchid*
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In case anybody else out there is as obsessive as me...
http://blog.orphi.me.uk/archives/312
--
http://blog.orphi.me.uk/
http://www.zazzle.com/MathematicalOrchid*
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> In case anybody else out there is as obsessive as me...
>
> http://blog.orphi.me.uk/archives/312
...or in tabular form...
http://blog.orphi.me.uk/about/temperatures
--
http://blog.orphi.me.uk/
http://www.zazzle.com/MathematicalOrchid*
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>> In case anybody else out there is as obsessive as me...
>>
>> http://blog.orphi.me.uk/archives/312
>
> ...or in tabular form...
>
> http://blog.orphi.me.uk/about/temperatures
Things that look shiny are often shiny to IR too (eg your gloss black oven
top, car paintwork, etc) - so you're going to be measuring the temperature
of whatever is being reflected more than the actual thing.
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4846e669$1@news.povray.org...
> In case anybody else out there is as obsessive as me...
>
> http://blog.orphi.me.uk/archives/312
>
Must we understand that you drop your choppen chicken in a COLD frying pan?
Marc
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scott wrote:
> Things that look shiny are often shiny to IR too (eg your gloss black
> oven top, car paintwork, etc) - so you're going to be measuring the
> temperature of whatever is being reflected more than the actual thing.
In the case of the car, that's going to be the sky (surely not that warm
on a cloudy day?) or the wall (presumably at equillibrium with the
surroundings). And yet, I got a fairly warm reading.
In the case of the cooker, that ought to be the gas flames. [Now there's
a question - can an IR thermometer measure the temperature of a flame?
Or will it measure the next solid object behind it?] Or, alternatively,
the underside of the flying pan. Either way, the temperature I measured
seemed pretty low.
If you wanted to be technical, presumably the IR arriving at the sensor
is the SUM of reflected and emitted? (What the computer calculates the
temperature at is another matter of course...)
--
http://blog.orphi.me.uk/
http://www.zazzle.com/MathematicalOrchid*
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m_a_r_c wrote:
> Must we understand that you drop your choppen chicken in a COLD frying pan?
For the purposes of Science, you understand. ;-)
--
http://blog.orphi.me.uk/
http://www.zazzle.com/MathematicalOrchid*
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> In the case of the car, that's going to be the sky (surely not that warm
> on a cloudy day?) or the wall (presumably at equillibrium with the
> surroundings). And yet, I got a fairly warm reading.
The objects are not 100% reflecting though, what I meant was your reading is
going to be lower than you expected because of the reflection.
> In the case of the cooker, that ought to be the gas flames. [Now there's a
> question - can an IR thermometer measure the temperature of a flame? Or
> will it measure the next solid object behind it?]
It works the same way as visible light. Can you see the next solid object
behind a flame? It depends how bright the flame is and how bright the
object is behind.
> If you wanted to be technical, presumably the IR arriving at the sensor is
> the SUM of reflected and emitted? (What the computer calculates the
> temperature at is another matter of course...)
The computer assumes the following equation, where e is the emissivity:
sensorReadingIR = emittedIR * e + reflectedIR * (1-e)
Rearranged:
emittedIR = ( sensorReadingIR - reflectedIR * (1-e) ) / e
It calculates reflectedIR from the "environment temperature" you program in
to it. You also tell it e, and of course it knows the sensorReadingIR. It
then calculates the temperature of the surface from emittedIR.
As you can imagine, if you program e to be 0.9, but you're actually
measuring something with a lower e, the computer is going to get the
calculation wrong and tell you it's at a lower temperature than it actually
is (assuming the object is hotter than the environment).
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4847cbc6$1@news.povray.org...
> m_a_r_c wrote:
>
>> Must we understand that you drop your choppen chicken in a COLD frying
>> pan?
>
> For the purposes of Science, you understand. ;-)
Oh well You're forgiven, then :-)
You can't expect Maillard's reactions with meat bathing in it's own juice :
Maillard reactions don't like moisture.
http://en.wikipedia.org/wiki/Maillard_reaction
That's why chiefs get food browned before proceeding to deglazing and obtain
an excellent 'jus'.
BTW I think you'd get hotter pan cooking 'plateau' temperature by dropping
the meat in yet hot pan because less water would be boiling at a time.
Marc
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