In article <477d49d8@news.povray.org>, war### [at] tagpovrayorg says...
> Patrick Elliott <sel### [at] rraznet> wrote:
> > Without knowing the size of the boat, the actual weight of the ball, an
d 
> > thus what the displacement will be from that, its not possible to 
> > project if the water will be "more" or "less" displaced by the inclusio
n 
> > of an entire cannon ball in the pool, versus a few millimeters of boat
 
> > sinking slightly more into the water from the weight.
> 
>   The size of the boat nor the weight of the ball make any difference on
> the original question: The original question didn't ask how much the wate
r
> level changes, it only asks if the water raises or lowers. To answer this
> question the only information needed is whether the cannonball has higher
> density than water or not. Since cannonballs are made of metal, the answe
r
> is yes. Thus its weight displaces more water than its volume, and thus
> the answer is that the water level lowers.
> 
Yeah. Read that later. Its not like I a) spend a lot of time thinking 
about these sorts of problems, or b) took physics in high school. Took a 
second English course, where I got to read all Sci-Fi stuff instead, so 
I still count as a nerd. ;) lol

-- 
void main () {

    if version = "Vista" {
      call slow_by_half();
      call DRM_everything();
    }
    call functional_code();
  }
  else
    call crash_windows();
}

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Kevin Wampler wrote:
> If you've been on the beach, you've probably noticed that the sand dries 
> out around you foot when you step on it, why is this?  Wouldn't you 
> expect a small puddle of water to form around your foot instead?

Here's the solution as I recall it:





The sand on the beach is actually in a more or less maximally compressed 
state before you step on it.  When you step on the sand, you compress it 
downward slightly, and to allow for this the sand under your foot 
expands outward somewhat.  Since the sand was about as dense as it could 
get at the beginning the end result of this downward compression and 
lateral expansion is that small gaps open up between the grains and the 
sand underneath your foot and its density actually *decreases*.  The 
water that was in that sand thus doesn't fill the whole empty volume 
anymore and drops to below the surface of the sand, causing the top of 
the sand to dry.

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Patrick Elliott wrote:
> is, will the displacement of the boat, from the cannon balls weight, be 
> larger or smaller than the displacement of the cannon ball itself? 

The cannonball sinks. That's why I included that part. :-)

(I used to say "bowling ball", until someone pointed out that most 
bowling balls actually float.)

-- 
   Darren New / San Diego, CA, USA (PST)
     It's not feature creep if you put it
     at the end and adjust the release date.

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"Darren New" <dne### [at] sanrrcom> wrote in message 
news:477ad72c$1@news.povray.org...
> You are sitting in a canoe, in a swimming pool, holding a cannon 
> ball in your lap. You throw the cannonball overboard, and it 
> sinks to the bottom. Does the level of water in the pool go up, 
> go down, or stay the same?
>
> (I've asked this of probably a dozen or more scuba dive 
> instructors, and only one has gotten it right. The reasoning 
> behind the correct answer is obvious once you hear it. I don't 
> remember if I got it right when I heard it.)
>
> -- 
>   Darren New / San Diego, CA, USA (PST)
>     It's not feature creep if you put it
>     at the end and adjust the release date.

Well that's interesting:

If one cannon ball level imperceptibly lowers;

If MANY cannon balls the swiiming pool will
fill tis cavity and eventually overflow;

Graphing the water level versus number of
cannon balls does not result in a linear
image.

Bonus points:
1. How many cannon balls before dip becomes rise?
(assume  CB V= .001 swimming pools and
CB density equals 7.87 g/mL)
2. What is the type name of such curves?
3. What kind of person would assume a swimming
pool could be *drained* by dropping cannon balls
into it?

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pan <pan### [at] syixcom> wrote:
> If one cannon ball level imperceptibly lowers;

> If MANY cannon balls the swiiming pool will
> fill tis cavity and eventually overflow;

  That can't happen in the problem because the canoe cannot stay afloat
with all those cannonballs.

-- 
                                                          - Warp

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pan wrote:
> "Darren New" <dne### [at] sanrrcom> wrote in message 
> news:477ad72c$1@news.povray.org...
>> You are sitting in a canoe, in a swimming pool, holding a cannon 
>> ball in your lap. You throw the cannonball overboard, and it 
>> sinks to the bottom. Does the level of water in the pool go up, 
>> go down, or stay the same?
>>
>> (I've asked this of probably a dozen or more scuba dive 
>> instructors, and only one has gotten it right. The reasoning 
>> behind the correct answer is obvious once you hear it. I don't 
>> remember if I got it right when I heard it.)
>>
>> -- 
>>   Darren New / San Diego, CA, USA (PST)
>>     It's not feature creep if you put it
>>     at the end and adjust the release date.
> 
> Well that's interesting:
> 
> If one cannon ball level imperceptibly lowers;
> 
> If MANY cannon balls the swiiming pool will
> fill tis cavity and eventually overflow;
> 
> Graphing the water level versus number of
> cannon balls does not result in a linear
> image.
> 
> Bonus points:
> 1. How many cannon balls before dip becomes rise?
> (assume  CB V= .001 swimming pools and
> CB density equals 7.87 g/mL)
> 2. What is the type name of such curves?
> 3. What kind of person would assume a swimming
> pool could be *drained* by dropping cannon balls
> into it?

1: If all the cannon balls are in the canoe to start with, then I don't
even see the canoe staying afloat.

2: Given 1, I would assume this is the 'magic canoe' type of curve. =)

3: The pool could not be completely drained by dropping equal sized
cannon balls into it. If the balls fall in a random close packing form,
the best you could get is about 65% of the volume of water out of the pool.

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