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In cubic_spline, the beginning and end points are control points, which are
similar to those of a bezier curve. If we take a bezier curve of a semi-circle
with a set of
<-3,0,0>,<-3,4,0>,<3,4,0>,<3,0,0>
The second and third points are the handles, which can be used in a spline as
#declare MySpline =
spline {
cubic_spline
-.25, <-3,4,0> // 2nd point of bezier
0, <-3,0,0> // 1st point of bezier
1, <3,0,0> // 4th point of bezier
1.25, <3,4,0> // 3rd point of bezier
}
#declare ctr = 0;
#while (ctr < 1)
sphere {
MySpline(ctr),.25
pigment { rgb <1-ctr,ctr,0> }
}
#declare ctr = ctr + 0.01;
#end
but it does not work, because I have no mechanism for setting/adjusting the
spline values.
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"Kima" <nomail@nomail> wrote:
> In cubic_spline, the beginning and end points are control points, which are
> similar to those of a bezier curve. If we take a bezier curve of a semi-circle
> with a set of
That won't work the way you expect, because POV-Ray doesn't do Bezier splines in
that section of its code. IIRC, all Bezier splines are cubic splines, but not
all cubic splines are Bezier splines.
I spent a LONG time working with Bezier splines and bicubic patches, and you
usually have to write your own code to do what you want.
> but it does not work, because I have no mechanism for setting/adjusting the
> spline values.
Given your code, I don't exactly know what that means.
User Cousin Ricky has solved this problem for you.
See here:
http://lib.povray.org/searchcollection/index2.php?objectName=SphereSweep&contributorTag=Cousin%20Ricky
:)
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The link was very handy, and I had not come across it before. Thanks, it helped
a lot.
>
> all Bezier splines are cubic splines, but not
> all cubic splines are Bezier splines.
>
Doesn't this mean that we can use a set of Bezier points as a cubic_spline?
>
> Given your code, I don't exactly know what that means.
>
The bezier points create a perfect semi-circle. But, the above cubic_spline does
not because I gave the values (-0.25, 0, 1, 1.25) randomly.
My question is: how to find these values (-0.25, 0, 1, 1.25) according to the
given bezier points?
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"Kima" <nomail@nomail> wrote:
> The bezier points create a perfect semi-circle. But, the above cubic_spline does
> not because I gave the values (-0.25, 0, 1, 1.25) randomly.
>
> My question is: how to find these values (-0.25, 0, 1, 1.25) according to the
> given bezier points?
http://news.povray.org/povray.general/thread/%3Cweb.5c47356c36095c6fbe7517870%40news.povray.org%3E/
http://news.povray.org/povray.binaries.images/thread/%3Cweb.5da27a2a65c96eb4eec112d0%40news.povray.org%3E/?ttop=428926&
mtop=428668&moff=8
http://news.povray.org/povray.general/thread/%3Cweb.5c407b748844a7763ca35f5e0%40news.povray.org%3E/
http://news.povray.org/povray.binaries.images/thread/%3C5b791075%40news.povray.org%3E/
http://www.povray.org/search/#gsc.tab=0&gsc.q=bezier%20circle&gsc.sort=
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