|
![](/i/fill.gif) |
And lo On Wed, 19 May 2010 12:52:17 +0100, Warp <war### [at] tag povray org> did
spake thusly:
> Phil Cook v2 <phi### [at] nospamrocain freeserve co uk> wrote:
>> The water is 'sucked' in because the cooling air inside the beaker
>> lowers
>> the pressure, but prior to that the air was hot and therefore should be
>> at
>> a higher pressure and force the water out of the beaker. Why does water
>> out not equal water in?
>
> The glass is put on the plate *after* the candle has been lit, so the
> air
> around the candle is already hot.
But the air around the "air around the candle" isn't as hot as it
transmits the heat along so you get a temperature gradient around the
candle prior to the beaker. Put the beaker over it and the air at the edge
cannot transmit the heat as quickly so it gets hotter.
> An interesting experiment would be to put the glass first and *then*
> light
> the candle to see what happens. (Of course you have to devise a way to do
> that. A magnifying glass and sunrays might be enough.)
Now that is something to try.
--
Phil Cook
--
I once tried to be apathetic, but I just couldn't be bothered
http://flipc.blogspot.com
Post a reply to this message
|
![](/i/fill.gif) |