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On Fri, 26 Sep 2008 19:44:56 +0200, Orchid XP v8 <voi### [at] dev null> wrote:
>
> I bet you can't overload ";", can you?
';' is not an operator. It is a statement terminator. It would make no
sense for a C++ program to redefine the meaning of ';'.
> In Haskell, you can. >:-D
Can you overload/redefine '->' in Haskell? What about '()'?
--
FE
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