On Mon, 31 Aug 2009 04:48:08 -0400, SharkD <mik### [at] gmailcom> wrote:

>I have the following formula:
>
>	tan(theta) * R1 = sin(theta) * R2
>
>R1 and R2 are known. How do I solve for theta? Thanks!
>
>-Mike

It has been a very, very long time since  I did anything like this and I could
be far out. So don't take this for gospel ;)

tan(theta) * R1 = sin(theta) * R2

Therefore: tan(theta)  = sin(theta)  * r2/r1

But tan(theta)  = sin(theta) /cos(theta)  

Therefore: sin(theta) /cos(theta)  = sin(theta)  * r2/r1

Divide both sided by sin(theta) /cos(theta)  

1 = (sin(theta) * cos(theta) *r2)/(r1 * sin(theta) )

1 = cos(theta)  *r2/r1

Therefore: cos(theta)  = r2/r1

-- 

Regards
     Stephen

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