Christopher James Huff <chr### [at] maccom> wrote in news:chrishuff-
EC5### [at] netplexaussieorg

> No. You obviously don't know what a gradient is...it is the slope, or 

I do, ony I thought that only "vissible" (f(x,y,z) > threshold) part do 
matter.

> "rate of change" of the function. The gradient of your function 
> increases in the x and y directions, so bigger bounding boxes require 
> higher max_gradient values. If you don't increase that value, the solver 
> fails to find a surface.

Where can I find detailed explenation of how solver works, best - with some 
step-by-stem examples how he do it ?

-- 
#macro g(U,V)(.4*abs(sin(9*sqrt(pow(x-U,2)+pow(y-V,2))))*pow(1-min(1,(sqrt(
pow(x-U,2)+pow(y-V,2))*.3)),2)+.9)#end#macro p(c)#if(c>1)#local l=mod(c,100
);g(2*div(l,10)-8,2*mod(l,10)-8)*p(div(c,100))#else 1#end#end light_source{
y 2}sphere{z*20 9pigment{function{p(26252423)*p(36455644)*p(66656463)}}}//M

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