On Fri, 31 Mar 2000 23:11:20 -0500, John VanSickle
<van### [at] erolscom> wrote:

>Close enough for government work.  Take the 2nd derivative of the motion,
>which will be a vector inward of the curve.  From this subtract a vector
>representing the force of gravity; since gravity is down, the result will
>be mostly up, tilted by the amount of acceleration.  Normalize the
>result.  That's the new "up" vector for the object.

What do you mean, 'gravity' :) I was talking with spaceships in mind.

Hope your math works, I'll try it as well.


Peter Popov ICQ : 15002700
Personal e-mail : pet### [at] usanet
TAG      e-mail : pet### [at] tagpovrayorg

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