> Interesting too is that changing the z directional function to:
>
> function { 0.1+cos((select(x,(x+0.5)*2,(x*2)) * 2 * pi) - pi) * cos(pi /
> 2 - (1-(y+0.5))*pi) }
>
> gives a partial image.

   Yes, for me +1 gives one part, and -1 seems to give the rest.

--
jaime

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