> Thus -- assuming I got the colour physics right on this one -- for
> proper representation of the actual Munsell pigments you'd need to
> divide the pigment colours by the colour of illuminant C, in order to
> undo the presumed white point bias. (Theoretically you'd need to to this
> in continuous spectrum space; in practice, you should do this in either
> XYZ or sRGB space, but whatever you choose it will be imprecise.)

That sounds about right.

What is also worth mentioning is that the human vision system is very 
good at figuring out what that underlying "unbiased" colour is by doing 
the division for you automatically. It figures out the illuminant colour 
from the surrounding view, so can be tricked/misled. What this means is 
that you could have exactly the same RGB value on two different coloured 
backgrounds, and you will be convinced the RGB value is different.

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