On 13-10-2014 3:10, Bald Eagle wrote:
> OK, after I got that all squared away, I worked out a shape that very closely
> approximates the curvature of the actual medallion, and then after some further
> frustration in trying to get THAT mapped it looks pretty good.
>
> Left and top is the hemispheroid, and right, center, and bottom are the modeled
> medallion shape.
>

Yes, this will certainly do indeed.

Thomas

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