>> 2:I know irradiance 1.08279（W/(m2*nm).I have converted XYZ to
>> the values
>> of color rgb using formula,my conversion formula is:
>> r=(3.2406*3.815429E-06)+(-1.5372*1.523114E-06)
>> g=(-0.9689*3.815429E-06)+(1.8758*3.815429E-06)
>> b=(0.0557*3.815429E-06)+(-0.2040*3.815429E-06)
>> but the value of b is negative,it must be something wrong in it.
>
> As I said in another post, if b is negative this indicates that the
> colour of your light source is outside the sRGB colour space. There is
> nothing physically wrong with that, sRGB only represents a portion of
> the colours we can see. Your light source is 817nm which is well into
> infra-red, a camera will see it but humans will struggle - that's why
> your calculated rgb values are so tiny and negative.
>

In this case, it may advisable to work on so called "false colours" 
where the actual spectrum is shifted and stretched or compressed to make 
it fit within the visible range.

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