> On 10-9-2011 14:23, Ive wrote:
>> Well, assuming you are *not* talking about HDR values but actually mean
>> "<213,127,79> / 255" what is wrong with using the functions given within
>> my very first reply?
>>
>> #macro scRGB_to_sRGB(Color)
>> rgb <sRGB_Gamma(Color.red),
>> sRGB_Gamma(Color.green),
>> sRGB_Gamma(Color.blue)>
>> #end
>
> No HDR! I shall try this indeed.
>
>>
>> if you need the inverse transformation or actually want to input values
>> in 8bit (0..255) range I'll leave it up to you to write these macro as
>> an exercise ;)
>
> <grin> I am not really good at this. I am even awfully moronic to tell
> the truth ;-)
>
>>
>> But what I do not get is why you do not simply type srgb <whatever
>> values> when you are actually using sRGB values (e.g. from a color
>> picker) and rgb <whatever values> when using linear values.
>
> Well mainly because color pickers give values as rgb. If I want to use
> that same shade as srgb, for example in Poseray, I do not know what the
> corresponding values are. However, your functions may help me with that
> indeed! Thanks!!
>
> Thomas

Almost all colour pickers, like the ones in Gimp or Paint, work in sRGB 
space. They assume a source encoded in sRGB space and return a value 
that is assumed to be used in the sRGB space.
Just try picking colour for 25%, 50% and 75% grays and see the actual 
results...



Alain

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