Chrisir wrote:

> What would be the formula to get
> 
> CX=
> CY=
> CZ=
> 
> based on AX,AY,AZ and BX,BY,BZ?
> 
> So there's a straight line from A to B to C.

That's probably not what you actually want, otherwise
the balls would stay unmoving in the image? But if you
have points A and B, then V=B-A will be a vector from
A to B and, e.g. C = A + 2*V will be point such as
you describe (you didn't specify distance).

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