Le 28/09/2010 10:09, Invisible a écrit :
> Question: If you have one of those gizmos that transforms rotational
> motion to reciprocating motion, what path does the reciprocating part
> trace?
> 
> Answer: As far as I can tell, the path is
> 
>   cos a + Sqrt(k^2 - sin^2 a)
> 
> where k is the length of the connecting rod that is free to pivot. As
> you can see, that means that for large k, the path is approximately a
> sine wave. However, for small k it deviates significantly from a simple
> sine wave...

You are also forgetting in the equation the offset between the axes
(when the center of rotation is not aligned with the translation path).


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