14.03.2010 18:39, gharryh пишет:
> The following problem:
>
>  From a triangle from whom i know the length of both legs (A and B) i want to
> calculate the longest leg (C).
> As i remember from school its C*C=A*A+B*B where A=62.5 and B=17.
> Translated into PovRay its C=sqrt(pow(A,2)+pow(B,2)) but the result is much
> smaller. The correct result for C should be +/-32.596

it works only if angle between A and B is equal 90 degrees, in other 
case use e.g. theorem of sinus

A/sin(alpha) = B/sin(beta) = C/sin(gamma)

>
> Code:
> #local RH=149;  // Rail Height
> #local FW=125;  // Flange Width
> #local HT=65.4; // Head Width at Top
> #local HB=70;   // Head Width at Base
> #local HH=39.8; // Head Height
> #local WT=14;   // Web Thickness
> #local FE=10.5; // Flange Thickness at Edge
> #local FM=27.5; // Flange Thickness at Center
> #local Y_X=76;  // Gravity Center
> #local FMT=degrees(atan((FM-FE)/(FW/2)));
> //c = sqrt( pow( a , 2) + pow( b , 2 ) ) .
> #local FE_FM=sqrt(pow((FM-FE),2)+pow(FE/2,2));
>
> box{<0,FM,0><FE_FM,0,1>  Rotate_Around_Trans(<0,0,-FMT><0,FM,0>) pigment {Red}}
>
> End Code
>
> But maybe there is a error in the box code becourse is i replace FE_FM with that
> value is displayed wrong also.
>
> Regards
>
> Harry
>
>
>

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