Invisible wrote:
> Vincent Le Chevalier wrote:
>> so the bounds for X are
>> X0 = X( atan(-B/A tan K) )
>> X1 = X( pi + atan(-B/A tan K) )
> 
> My God, man, IT WORKS!

That's the good thing about math, you know :-)
More than the result you should keep the method in mind, it's useful in 
plenty of problems...

-- 
Vincent

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