Darren New wrote:
> Invisible wrote:
>> Wouldn't that be increadibly unstable, numerically?
> 
> How could it be?  If you're taking the limit of something that's going 
> to a finite value in a continuous curve, how could your calculation of 
> the value closer to the limit have more error than the error calculated 
> farther from the limit?

According to Google calculator, sin(1e-14)/1e-14 = 1, but 
sin(1e-15)/1e-15 = 0.

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