> Wikipedia informs me that what you're looking for is a "binomial
> distribution".
Thanks - that was the key I needed!
> According to this, we have the probability of getting exactly K heads as
>
> (N choose K) * P(H)^K * (1 - P(H))^(N-K)
That *is* useful, at least using this formula I get correct results,
although it's still a bit clumsy.
I will continue with Excel now trying to make it a bit neater.
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