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>> Uh, no, the *cyan* lense is supposed to block red. The *red* lense is
>> supposed to let it through. It shouldn't be blocking it at all.
>
> It should make it not visible at all which I think is what Greg meant.
>
> Through the red lens, light coming from the cyan parts is filtered out,
> therefore the cyan parts are visible in black. Light coming from the
> red parts and light coming from the white parts should in theory end up
> at exactly the same color, thus you can't distinguish the red parts when
> you look through the red lens.
Or rather, with the red lense, black appears as black, red appears as
red, and any other colour appears as black. (At least, ideally.)
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