>> Uh, no, the *cyan* lense is supposed to block red. The *red* lense is 
>> supposed to let it through. It shouldn't be blocking it at all.
> 
> It should make it not visible at all which I think is what Greg meant.
> 
> Through the red lens, light coming from the cyan parts is filtered out, 
>  therefore the cyan parts are visible in black. Light coming from the 
> red parts and light coming from the white parts should in theory end up 
> at exactly the same color, thus you can't distinguish the red parts when 
> you look through the red lens.

Or rather, with the red lense, black appears as black, red appears as 
red, and any other colour appears as black. (At least, ideally.)

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