SharkD wrote:
> On 11/17/2009 7:45 AM, SharkD wrote:
>> sind(60)/3
>>
>> Mike
> 
> cosd(30)/3

So sqrt(1/12) is it then!


As a side note, the only equation I was able to find which fit the last 
digit of "9" which you included was:


2 - 1/(gamma[19/24]^2 * ln[ChampernowneNumber[10]] * zeta[3])

(formatted so you can type it into Wolfram Alpha)

Which clearly is highly unlikely to be what your number came from, so it 
looks like Vincent's hypothesis is pretty surely the correct one.

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