Invisible wrote:
> So presumably the derivative of f(f(f(x))) is going to be something like > f'(f(f(x))) * f'(f(x)) * f'(x)? And in general, the Nth composition will > be ever more complex as N increases?> > Oh dear.
Ooo, but wait... The Nth derivative of a polynomial will be zero if N
exceeds the order of the polynomial. Hmm.
