> Easier if at this step:
>
> sin(theta)/cos(theta)  = sin(theta)  * r2/r1
>
> You just cancel the sin(theta) term on each side, leaves you with:
>
> 1/cos(theta) = r2/r1

However, now that you've divided both sides by sin(theta), you're only 
solving the equation over values where sin(theta) is not 0. You have to 
check that possibility separately, and it looks like the equation is 
trivially true when sin(theta) = 0, or when theta = n*pi. (As well as the 
solution you gave.)

 - Slime
 [ http://www.slimeland.com/ ]

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