Darren New <dne### [at] sanrrcom> wrote:
> Yes! Precisely. You're not changing the value of 5. You're changing the 
> value of 'a'.

  I'm sorry, but I'm having difficult time understanding what you are
talking about. It just seems inconsistent and incoherent.

  In a previous post you argued how you are not changing the value of 'a'
and now you are saying that you are.

> Contrast with
> a = " hello  "; b = a;  a.trim();

> Whether you changed 'b' depends on whether string literals have value or 
> reference semantics. *Unless* strings are read-only, in which case a.trim() 
> returns a new string which gets discarded.

  I don't really understand what's your point.

-- 
                                                          - Warp

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