On 8-2-2010 13:53, Warp wrote:
>   In many tabletop games where a d100 is required, it's a common trick to
> throw two (differently-colored) d10's instead, and use one of them
> multiplied by 10 and the other as is (because a physical d100 is very
> cumbersome and impractical to use). For example, if you throw a white d10
> and a black d10, the white could be used as the tens, and the black one
> as the ones. The end result is the same as when throwing a d100: An even
> distribution. (Many die sets even contain a d10 with multiples of 10
> instead of regular 0-9 numbers, for this exact purpose.)
> 
>   However, suppose that you use a variant of this: Throw two d10's and
> then the larger result is always used as the tens, and the other as the
> ones. (So for example if you throw a 7 and a 2, then the result is 72,
> but if it had been a 2 and a 7, the result would still be 72.)
> 
>   What is the probability distribution now?
> 
any multiple of 11 has a probability of 1/100.
if the numbers are not the same the one where the 10 has a higher value 
than the 1 has a probability of 2/100. the rest has probability 0
Integrate if you need a percentile.

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