> Unless my eyes deceive me, this is equivilent:
>
> J = 2a^3 - 9ab + 26c
> K = Sqrt(J^2 + 4(-a^2 + 3b)^3)
> M = (1 + i Sqrt(3))/2
> N = (-1 + i Sqrt(3))/2
>
> r1 = -(a/3) + Cbrt((-J + K)/54) + Cbrt((-J - K)/54)
> r2 = -(a/3) + M Cbrt((-J + K)/54) + N Cbrt((-J - K)/54)
> r3 = -(a/3) + N Cbrt((-J + K)/54) + M Cbrt((-J - K)/54)
>
> While hardly on the same level as the quadratic, it's not "that" hard.
Did you try to derive those equations from ax^3+bx^2+cx+d=0 ?? :-)
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