Chris Cason wrote:

> If he wants brevity he could also code it like this:
> 
>   for (int i = 0; i < c.size(); i++)
>     out.append(c[i] ? "1" : "0");
> 
> which is just as valid and avoids running the if/else together.

Ooo, I like that. (It makes it clear that append() is always called, and 
it's only the argument that changes depending on c[i].)

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