scott wrote:

> No it's not equal, it's proportional to cos(x), that is what lambertian
> means.  It then "looks" the same brightness to a camera/eye/surface from
> any angle, because the area you see for each pixel/cone/rod/patch is
> proportional to 1/cos(x), so the cos factor cancels out leaving constant
> "brightness" from any angle.

I have to ask about this. Many sources say that radiance is analogous to
luminance. And they also say that luminance "is most often used to
characterize the brightness". Like here:

http://www.optics.arizona.edu/Palmer/rpfaq/rpfaq.htm

So that means radiance also describes "brightness"?? And lambertian
surface has equal brightness no matter where you look at it from if the
light source remains stationary.

So what is the deal here?

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