Tim Attwood napsal(a):
>>>       #local result = result + vlength(V2-V1);
>> In the particular case of a spline, we know the derivative vector at any
>> point. I suspect it would be more accurate to use its length rather than 
>> the
>> distance between two consecutive points.
> 
> I don't follow, maybe you could explain that?
> I've read through a book on topology a while back and it
> seemed very dense to me, isn't a derivative vector a
> derivative in respect to a vector field? A vector field
> being a mapping from R^n to R^n? I think in this case
> a spline is a mapping from R to R^3, doesn't that
> rule out some of this sort of math? Remember that
> we don't know the type of spline here either. 
> 
> 
A derivative is always with respect to a scalar and any vector is 
differentiable. An operator over R^n -> R^n is a divergence (nabla dot).
R^3 -> R^3 has a rotation (nabla cross) aditionally.
R^n -> R (a scalar field) has a gradient (nabla; vector of derivations 
along axes).

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