Orchid XP v7 wrote:

> (Although if you're bothering to compute the coefficients of a quadratic
> equation, it seems a shame to compute them all over again to find the
> second point of intersection...)

Well, I use the simplified form I posted to this thread. It is
computationally quite simple. So it all boils down to how often you
actually need the "unneeded" intersection and what is the net effect. I
haven't measured it.

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